Supercuspidal

adj

adj ·Rare ·Advanced level

Definitions

Adjective
  1. 1
    That has a zero Jacquet functor for every proper parabolic subgroup not-comparable

    "A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k)."

Example

More examples

"A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k)."

Etymology

From super- + cuspidal.

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Data sourced from Wiktionary, WordNet, CMU, and other open linguistic databases. Updated March 2026.